Of the following compounds, which has the highest boiling point?

H_{2} S

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C H_{3} - C H_{2} O H

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C H_{3} - C O O H

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C H_{3} - C O H

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Solution

The correct option is C $C H_{3} - C O O H$
Boiling point of $H_{2} S - (- 60^{0} C)$
Boiling point of ${C H}_{3} - {C H}_{2} - O H - ({78.5}^{0} C)$
Boiling point of ${C H}_{3} - C O O H - (118^{0} C)$
Boiling point of ${C H}_{3} - C H O - ({20.2}^{0} C)$
$∴ {C H}_{3} - C O O H$ has highest boiling point.
Acetic acid shows the highest boiling point among the given compound due to the intermolecular hydrogen bonding.

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Which of the following compounds gives fastest reaction with HBr and why

(i) (CH3)3 COH

(ii) CH3 CH2 CH2OH

(iii) CH3 CHOH CH3

(iv) CH3 (CH3) CH CH2OH

C H_{3} - N H_{2}

C H_{3} - N H - C H_{3}

C H_{3} - N | C H_{3} - C H_{3}

C H_{3} - C H O, C H_{3} - C H_{2} - O H, C H_{3} - C H_{2} - C H_{3}

C H_{3} - C H = C H - C H_{2} O H \to C H_{3} - C H = C H - C O O H

{C H}_{3} - {C H}_{2} - C H | {C H}_{2} C I - {C H}_{2} O H | C H - C H | {C H}_{3} - {C H}_{3}

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