Question

Of the following statements :
$\left(P\right)C_6{H}_{5}N=CH-C_6{H}_5$ is a Schiff's base.
$\left(Q\right)$A dye is obtained by the reaction of aniline and $C_6{H}_5{N}^{+}\equiv NCl$.
$\left(R\right)C_6{H}_{5}C{H}_{2}N{H}_2$ on treatment with $[NaN{O}_2+HCl]$ gives diazonium salt.
$\left(S\right)p-$Toluidine on treatment with $[HN{O}_2+HCl]$ gives diazonium salt.

• A. only $\left(P\right)and\left(Q\right)$ are correct
• B. only $\left(P\right)and\left(R\right)$ are correct
• C. only $\left(R\right)and\left(S\right)$ are correct
• D. $\left(P\right),\left(Q\right)$and$\left(S\right)$ are correct

Answer 1

The correct option is D $\left(P\right),\left(Q\right)$and$\left(S\right)$ are correct

A Schiff base is a substituted imine$(R_{2}C=N-R^{\prime })$. It is used as antioxidant. Thus $\left(P\right)C_6{H}_{5}N=CH-C_6{H}_5$ is a Schiff's base. Thus statment $\left(P\right)$ is correct.

Aniline reacts with $C_6{H}_5{N}^{+}\equiv NCl$ to form higly coloured azo dye. This reaction is known as azo coupling. Thus the statement $\left(Q\right)$ is correct.

$C_6{H}_{5}C{H}_{2}N{H}_2$ is a primary aliphatic amine. When it is treated with $[NaN{O}_2+HCl]$, it gives unstable diazonium salt which decomposes to form benzyl alcohol. Hence, statement $\left(R\right)$ is incorrect.

p-Toluidne is an aromatic primary amine. Hence, it on treatment with $[NaN{O}_2+HCl]$ gives diazonium salt. Hence, statement $\left(S\right)$ is correct.

Option D is correct.