You visited us 1 times! Enjoying our articles? Unlock Full Access!

Carbylamine Test

Reaction of a...

Question

Reaction of aniline with $H N O_{2}$ followed by treatment of dilute acid gives :-

C_{6} H_{5} N H O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} N H N H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C_{6} H_{5} O H$
Reaction of aniline with $H N O_{3}$ followed by treatment of dilute acid refers the structure.
ence, the product is $C_{6} H_{5} O H$ .

Suggest Corrections

Similar questions

(P) C_{6} H_{5} N = C H - C_{6} H_{5}

(Q)

C_{6} H_{5} N^{+} \equiv N C l

(R) C_{6} H_{5} C H_{2} N H_{2}

[N a N O_{2} + H C l]

(S) p -

[H N O_{2} + H C l]

H N O_{2}

H C l

0^{\circ} C

50 %

H_{2} O_{2}

Join BYJU'S Learning Program