Question

Of the four oxyacids of chlorine, the strongest oxidizing agent in dilute aqueous solution is

• A. $HCl{O}_4$
• B. $HCl{O}_3$
• C. $HCl{O}_2$
• D. $HOCl$

Answer 1

The correct option is A $HCl{O}_4$

$HCl{O}_4$ is strongest oxidizing agent as $Cl$ has the highest oxidation number of +7 in it. The correct order is HClO < $HCl{O}_2$ < $HCl{O}_3$ < $HCl{O}_4$