You visited us 1 times! Enjoying our articles? Unlock Full Access!

Covalent Bond

Of the O2-,...

Question

Of the ${O_{2}}^{-}, {O_{2}}^{2 -}$ and $O_{2}$ , $O_{2 -}^{-}$ has odd bond order and $O_{2}$ and $O_{2}^{-}$ are diamagnetic.
Answer whether the above statement is true or false.
If true enter 1, else enter 0.

Open in App

Solution

The MO of $O_{2}$ is given:
The bond order of $O_{2} = \frac{8 - 4}{2} = 2$
The bond order of ${O_{2}}^{-} = \frac{8 - 5}{2} = 1.5$
The bond order of ${O_{2}}^{2 -} = \frac{8 - 6}{2} = 1$
Hence, ${O_{2}}^{2 -}$ has odd bond order i.e. 1 and $O_{2}$ and ${O_{2}}^{-}$ are paramagnetic as they have unpaired electrons in their anti-bonding orbital.

Suggest Corrections

Similar questions

O_{2}

O_{2}^{-}

K O_{2}

O_{2}

C O_{2}

K O_{2}

C O_{2}

O_{2}

K O_{2}

H C O_{3}^{-}

N_{2}

N_{2}^{+}

N - N

O_{2}

O_{2}^{+}

O - O

Join BYJU'S Learning Program