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Molecular Orbitals of Helium and Lithium

When O2 cha...

Question

When $O_{2}$ changes to $O_{2}^{-}$ the O - O bond distance increases and bond order decreases.
If true enter 1, else enter 0.
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Solution

The correct option is A 1
$O_{2}$ has 16 electrons
$(σ 1 s)^{2}, (σ^{} 1 s)^{2}, (σ 2 s)^{2}, (σ^{} 2 s)^{2}, (2 p_{z})^{2}, (π)^{4}, (π^{})^{2}$
a is the number of electrons in bonding molecular orbitals and
b is the number of electrons in antibondng molecular orbitals.
Bond Order $= \frac{1}{2} (10 - 6)$
$= 2$
$O_{2}^{-}$ has 17 electrons
$(σ 1 s)^{2}, (σ^{} 1 s)^{2}, (σ 2 s)^{2}, (σ^{} 2 s)^{2}, (2 p_{z})^{2}, (π)^{4}, (π^{})^{3}$
Bond Order $= \frac{1}{2} (10 - 7)$
$= 1.5$
hence bond order decreases and bond distance increases as bond distance is inversely proportional bond order.

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