The correct option is C 16
Let the three distinct numbers be x, y and z.
Given: x+y=25,…..(i)
y+2z=45,…..(ii)
z+2x=40…..(iii)
From (i),y=25–x
Substituting y=25–x in (ii), we get
25–x+2z=45
⇒–x+2z=20…..(iv)
Multiplying (iv) by 2, we get
–2x+4z=40…..(v)
Now, adding (iii) and (v), we get
(–2x+4z)+(z+2x)=40+40
⇒5z=80
⇒z=16
Thus, the third number is 16.
Hence, the correct answer is option (3).