Question

$-OH$ cannot be replaced by $-Cl$, if we use:

• A. $PC{l}_5$
• B. $PC{l}_3$
• C. $S_{2}C{l}_2$
• D. $SOC{l}_2$

Answer 1

Answer: (C)

$S_{2}C{l}_2$

$-OH$ cannot be replaced by $-Cl$ while reaction with $S_2{Cl}_2$ because except $S_2{Cl}_2$ all other are strong chlorinating agent which react with alcohols to give alkyl halides.

On the other hand, it requires more energy to break $S-S$ bond for further reaction with alcohols.

Option C is correct