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Question
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day?
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day?
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Solution
The correct option is B $0.40
On day 1, 1 part Juice + 1 part Water = 2 parts of Mixture.On day 2, 1 part Juice + 2 parts Water = 3 parts of Mixture.Revenue for day 1 = 2 parts × 0.60And Revenue for Day 2 = 3 parts × P; where P is the price per glass on day 2.So, P = 2×0.63=0.4 $ (option D)
On day 1, 1 part Juice + 1 part Water = 2 parts of Mixture.
On day 2, 1 part Juice + 2 parts Water = 3 parts of Mixture.
Revenue for day 1 = 2 parts × 0.60
And Revenue for Day 2 = 3 parts × P; where P is the price per glass on day 2.
So, P = 2×0.63=0.4 $ (option D)
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