Question

on a certain hill station pure water is found to kelvin is boil at 95 degree Celsius how many gram of NaCl must be added to 2 kg of water so that it boil at hundred degree Celsius

Answer 1

Dear student,

According to the elevation in B.P. of the formula $$\begin{gathered} ∆T_b=K_b\times molalityofsolution \\ (100-95)=0.52\times \frac{no.ofmolesofsolute}{massofsolventin\left(kg\right)} \\ 5=0.52\times \frac{n}{2} \end{gathered}$$

n = 19.2
mass of NaCl = 19.2 x 58.5 = 1123.2 gm
Regards