Question

On a morning walk, three persons step off together and their steps measure $40$ cm, $42$ cm and $45$ cm, respectively.

What is the minimum distance each should walk so that each can cover the same distance in complete steps?

Answer 1

Solve for the LCM of the distance:

To determine the minimum distance each should walk so that each can cover the same distance in complete steps, we find the LCM.

$$\begin{gathered} 40=2\times 2\times 2\times 5 \\ 42=2\times 3\times 7 \\ 45=3\times 3\times 5 \end{gathered}$$

So, LCM of $40,42,45$ is $2\times 2\times 2\times 5\times 3\times 3\times 7=2520cm$

Hence, the minimum distance to cover is $2520cm$.