Question

On a particular day the number of vehicles passing through a crossing is as follows. Two wheelers = 57; Three wheelers = 33; Four wheelers = 30. A particular vehicle is chosen at random, what is the probability that it is not a four wheeler.

Answer 1

Total number of vehicles = 57 + 33 + 30 = 120
Total number of four wheelers = 30
Vehicles that are not four wheelers = Total number of vehicles -Vehicles that are four wheelers
= 120 - 30
= 90

P(not a four wheeler) =$\frac{\mathrm{Number}\mathrm{of}\mathrm{vehicles}\mathrm{that}\mathrm{are}\mathrm{not}\mathrm{four}\mathrm{wheeler}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{vehicles}}=\frac{90}{120}=0.75$