On a particular day- the number of vehicles passing through a crossing is given below-WlineVehicle - Two wheeler - Three wheeler - Four wheelerll WlineFrequency - 57 - 33 - 30II Wline array A particular vehicle is chosen at random- What is the probability that is not a four wheeler-

Total space = 57 + 33 + 30 = 120 Four wheeler = 30 So, probability = 30/120 = 1/4 ...

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On a particul...

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On a particular day, the number of vehicles passing through a crossing is given below :
$\begin{matrix} V e h i c l e & T w o w h e e l e r & T h r e e w h e e l e r & F o u r w h e e l e r F r e q u e n c y & 57 & 33 & 30 \end{matrix}$
A particular vehicle is chosen at random. What is the probability that is not a four wheeler.

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Solution

Total space = 57 + 33 + 30 = 120
Four wheeler = 30
So, probability = $\frac{30}{120}$
$= \frac{1}{4}$

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On a particular day, at a crossing in a city, the various types of 240 vehicles going past during a time interval were observed as under:
$\begin{matrix} T y p e o f v e h i c l e & T w o - w h e e l e r s & T h r e e - w h e e l e r s & F o u r - w h e e l e r s F r e q u e n c y & 84 & 68 & 88 \end{matrix}$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

On a particular day, at a crossing in a city, the various types of vehicles going past during a time interval were observed as follows:
$\begin{matrix} Type of vehicle & Two-wheelers & Three-wheelers & Four-wheelers Frequency & 84 & 68 & 88 \end{matrix}$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

On a particular day, at a crossing in a city, the various types of 240 vehicles going past during a time interval were observed as under:

$\begin{matrix} Type of vehicle & Two-wheelers & Three-wheelers & Four-wheelers Frequency & 84 & 68 & 88 \end{matrix}$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

On a particular day, at a crossing in a city, the various types of 240 vehicles going past during a time interval were observed as under:
$\begin{matrix} Type of vehicle & Two-wheelers & Three-wheelers & Four-wheelers Frequency & 84 & 68 & 88 \end{matrix}$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

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On a particular day, the number of vehicles passing through a crossing is given below : VehicleTwo wheelerThree wheelerFour wheelerFrequency573330 A particular vehicle is chosen at random. What is the probability that is not a four wheeler.

Total space = 57 + 33 + 30 = 120 Four wheeler = 30 So, probability = 30120 =14

Total space = 57 + 33 + 30 = 120
Four wheeler = 30
So, probability = $\frac{30}{120}$
$= \frac{1}{4}$