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Question
On a photosensitive material, when frequency of incident radiation is increased by 30% kinetic energy of emitted photo electrons increases from 0.4 eV to 0.9 eV. The work function of the surface is :
On a photosensitive material, when frequency of incident radiation is increased by 30% kinetic energy of emitted photo electrons increases from 0.4 eV to 0.9 eV. The work function of the surface is :
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Solution
The correct option is D 1.267 eV
As per Einstein's Photoelectric equation:K.E.max = hν−W 0.4 = h×ν−W --- (1)0.9 = h×1.3ν−W --- (2)
(2) - (1)0.5 = 0.3×hν⇒hν=1.667eVPutting this value in equation (1),W=1.667−0.4=1.267 eV
As per Einstein's Photoelectric equation:
K.E.max = hν−W
0.4 = h×ν−W --- (1)
0.9 = h×1.3ν−W --- (2)
(2) - (1)
0.5 = 0.3×hν⇒hν=1.667eV
Putting this value in equation (1),
W=1.667−0.4=1.267 eV
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