Question

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c{m}^2$.

__

Answer 1

Area of a square = $sid{e}^2$
Side of the square = 50 cm
Area of square Handkerchief = ${50}^2$ = 2500 $c{m}^2$
Area of circles = $\pi \times r^2$
Radius of the circle = 7 cm

Total area of circles = 7 x $\frac{22}{7}$ x $7^2$ = 1078$c{m}^2$

Remaining area = 2500 - 1078 = 1422 $c{m}^2$