Question

On analysis of an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the given sample?

Answer 1

1 mole of nacl or 58.5g pure NaCl contains 35.5 g chlorine

% Chlorine in pure NaCl =$\frac{35.5}{58.5}\times 100$ =60.7%

100% pure sample $\to$ 60.7% chlorine

Therefore, x% pure sample $\to$ 45.5% chlorine

x=$\frac{45.5}{60.7}\times$ =74.95% pure.