Question

Question 22

On dividing $57p^{2}qr$ by $114pq$, we get
a) $\frac{1}{4}pr$
b) $\frac{3}{4}pr$
c) $\frac{1}{2}pr$
d) $2pr$

Answer 1

c) $\frac{1}{2}pr$

$\to$​​​​​​​Required value =
$\frac{57p^{2}qr}{114pq}=\frac{57\times p\times p\times q\times r}{114\times p\times q}=\frac{57}{114}pr=\frac{1}{2}pr$