On dividing $p (4 p^{2} - 16)$ by $4 p (p - 2),$ we get (a) $2 p + 4$ (b) $p + 2$

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Solution

$p (4 p^{2} - 16) = 4 p (p^{2} - 4) = 4 p (p^{2} - 2^{2}) = 4 p (p - 2) (p + 2)$
$p (4 p^{2} - 16) \div 4 p (p - 2) = \frac{p (4 p^{2} - 16)}{4 p (p - 2)} = \frac{4 p (p - 2) (p + 2)}{4 p (p - 2)} = p + 2$
The answer is $(b)$

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