On drawing the graphs of the linear equations $4 x - 3 y + 4 = 0$ and $4 x + 3 y - 20 = 0$ the area bounded by this line and $x$ axis is

10 s q

units

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12 s q

units

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5 s q

units

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6 s q

units

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Solution

The correct option is B $12 s q$ units
REF.Image.
$4 x - 3 y + 4 = 0$ ${\begin{matrix} w h e n x = 0 y = 4 / 3 w h e n y = 0 x = - 1 \end{matrix}$
$4 x + 3 y - 20 = 0$ $⎧ ⎨ ⎩ \begin{matrix} w h e n x = 0 y = \frac{20}{3} w h e n y = 0 x = 5 \end{matrix}$
Both lines intersect at (2, 4)
$(∵$ by solving given lines).
Area $= \frac{1}{2} \times 6 \times 4 = 12 u n i t s .$

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