Question

On giving energy, which of the following orbitals having the following quantum numbers will lose electron first?

• A. $n=4$, $l=0$
• B. $n=3$, $l=2$
• C. $n=3$, $l=1$
• D. $n=2$, $l=1$

Answer 1

The correct option is A $n=4$, $l=0$

We know, electrons which are present in the outermost orbital are the most loosely bound electrons.
Principal quantum number defines the shell of the electron.
Thus the electron residing in the orbital $n=4,l=o$ will be removed first.