Question

On heating ammonium dichromate and barium azide separately we get:

• A. ${\mathrm{N}}_2$ in both cases
• B. ${\mathrm{N}}_2$ with ammonium dichromate and $\mathrm{NO}$ with barium azide
• C. ${\mathrm{N}}_2\mathrm{O}$ with ammonium dichromate and $\mathrm{NO}$ with barium azide
• D. ${\mathrm{N}}_2\mathrm{O}$ with ammonium dichromate and ${\mathrm{N}}_2$ with barium azide

Answer 1

The correct option is A

${\mathrm{N}}_2$ in both cases

The explanation for Correct Answers:

Option (A) ${\mathrm{N}}_2$ in both cases

• Ammonium dichromate produces Nitrogen gas on heating.

$\underset{\mathrm{Ammonium}\mathrm{dichromate}}{{\left({\mathrm{NH}}_4\right)}_2{\mathrm{Cr}}_2{\mathrm{O}}_7\left(\mathrm{s}\right)}\to \underset{\mathrm{Chromium}\mathrm{oxide}}{{\mathrm{Cr}}_2{\mathrm{O}}_3\left(\mathrm{s}\right)}+\underset{\mathrm{Water}}{4{\mathrm{H}}_2\mathrm{O}}\left(\mathrm{g}\right)+\underset{\mathrm{Nitrogen}}{{\mathrm{N}}_2\left(\mathrm{g}\right)}$

• Barium azide produces Nitrogen gas on heating.

$\underset{\mathrm{Barium}\mathrm{azide}}{\mathrm{Ba}{\left({\mathrm{N}}_3\right)}_2\left(\mathrm{s}\right)}\to \underset{\mathrm{Barium}}{\mathrm{Ba}\left(\mathrm{s}\right)}+\underset{\mathrm{Nitrogen}}{3{\mathrm{N}}_2\left(\mathrm{g}\right)}$

Therefore, on heating Ammonium dichromate and barium azide separately we get ${\mathrm{N}}_2$ in both cases.