On heating blue coloured powder of copper(II) nitrate in a boiling tube copper oxide (black), oxygen gas and a brown gas X is formed. What is the balanced chemical equation for the reaction?

2 C u (N O_{3}) (s) H e a t - -- \to 2 C u O (s) + O_{2} (g) + 2 N O_{2} (g)

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C u (N O_{3})_{2} (s) H e a t - -- \to C u O (s) + N O_{2} (g)

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2 C u (N O_{3})_{2} (s) H e a t - -- \to 2 C u O (s) + O_{2} (g) + 4 N O_{2} (g)

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C u (N O_{3})_{2} (s) H e a t - -- \to C u (s) + N O_{2} (g)

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C u (N O_{3}) (s) H e a t - -- \to C u O (s) + N O_{2} (g)

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Solution

The correct option is C $2 C u (N O_{3})_{2} (s) H e a t - -- \to 2 C u O (s) + O_{2} (g) + 4 N O_{2} (g)$
On heating blue coloured powder of copper(II) nitrate in a boiling tube copper oxide (black), oxygen gas and a brown gas named as X is formed . The brown gas is nitrogen dioxide. ( $N O_{2}$ ).
The balanced chemical equation is
$2 C u (N O_{3})_{2} (s) h e a t - - \to 2 C u O (s) + O_{2} (g) + 4 N O_{2} (g)$
So the correct option is C

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