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Acid Rain

On heating co...

Question

On heating compound $(A)$ gives a gas $(B)$ which is a constituent of air. This gas when treated with $3$ mol of hydrogen $(H_{2})$ in the presence of a catalyst gives another gas $(C)$ which is basic in nature. Gas $C$ on further oxidation in moist condition gives a compound $(D)$ which is a part of acid rain. Identify compounds $(A)$ to $(D)$ and also give necessary equations of all the steps involved.

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Solution

$A = N H_{4} N O_{2};$ $B = N_{2};$ $C = N H_{3};$ $D = H N O_{3}$

As per the given condition:

(a) $N H_{4} N O_{2} \to N_{2} + 2 H_{2} O$
A B

(b) $N_{2} + 3 H_{2} c a t a l y s t - --- \to 2 N H_{3}$
B C

(c) $N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$
C D

Acid rain:

$2 N O + O_{2} \to 2 N O_{2}$

$3 N O_{2} + H_{2} O \to 2 H N O_{3} + N O$

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Question 59
A non-metal A, which is the largest constituent of air, when heated with $H_{2}$ in 1:3 ratio in the presence of catalyst $Fe$ , gives a gas B.
On heating with $O_{2}$ , it gives an oxide C. If this oxide is passed into water in the presence of air it gives an acid D, which acts as a strong oxidising agent.

(a) Identify A, B, C and D
(b) To which group of periodic table does this non-metal belong?

Q. On mixing the aqueous solutions of compounds

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N O_{2}

gas with a cracking noise. An aqueous solution of compound

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H_{2} S

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K_{2} C r O_{4}

Q. (i) A black mineral (A) on heating in presence of air gives a gas (B).
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H_{2} S O_{4}

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(iii) On passing gas (C) into an aqueous solution (B), a white turbidity is obtained.
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S O_{2}

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K F e^{I} I [F e^{I} I I (C N)_{6}]

If true enter 1, else enter 0.

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