On heating lead nitrate the product formed is :

N o

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N O_{2}

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N_{2} O

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N_{2} O_{5}

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Solution

The correct option is B $N O_{2}$
Reaction:
$P b (N O_{3})_{2} \to P b O + 2 N O_{2} + 1 / 2 O_{2}$

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Similar questions

Choose the correct answer :

(a) The nitrate salt which does not give a mixture of $N O_{2}$ and $O_{2}$ on heating is :

(i) $A g N O_{3}$ , (ii) $K N O_{3}$ ,

(iii) $C u (N O_{3})_{3}$ , (iv) $Z n (N O_{3})_{2}$ .

(b) The chemical used in the brown ring test is :

(i) $C u S O_{4}$ , (ii) $F e S O_{4}$

(iii) $F e_{2} (S O_{4})_{3}$ (iv) $Z n S O_{4}$ .

(i) NO, (ii) $N_{2} O,$

(iii) $N O_{2}$ (iv) $N_{2} O_{5}$ .

N O_{2}

A g N O_{3}

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