On hybridization of one s-orbital and one p-orbital we get:
A
mutual perpendicular orbitals
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B
two orbitals at 180∘ to each other
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C
four orbitals directed tetraheadrally
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D
three orbitals in one plane
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Solution
The correct option is D two orbitals at 180∘ to each other The number of hybrid orbitals is equal to the number of combining atomic orbitals. Therefore one s and one p will combine to give two sp orbital with maximum separation i.e. 180∘ apart.