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Standard XII

Physics

Carrier Concentration

On passing 0....

Question

On passing 0.1 Faraday of electricity through aluminium chloride, the

amount of aluminium metal deposited on cathode is

[MP PMT 1991]

0.9 gm

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0.3 gm

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0.27 gm

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2.7 gm

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Solution

The correct option is A
0.9 gm

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Similar questions

Q. On passing 0.01 Faraday of elctricity through a solution of aluminum chloride, the weight of Aluminium metal

(a t . w t . = 27)

deposited on cathode is:

On passing a current through a molten aluminium chloride for some time produced 11.28lit of $C l_{2}$ at NTP at anode. The quantity of aluminium deposited at cathode is:

Q. Aluminium oxide may be electrolysed at

1000^{\circ} C

to furnish aluminium metal (Atomic mass

= 27 a m u; 1 f a r a d a y = 96500 c o u l o m b

). The cathode reaction is:

A l^{3 +} + 3 e^{-} \to A l

To prepare

5.12 k g

of aluminium metal by this method we would require.

Aluminium oxide may be electrolyte at 1000 $^{0}$ C to furnish aluminium metal (Atomic mass = 27 amu, 1 Faraday = 96,500 Coulombs). The cathode reaction is $A l^{3} + 3 e^{-} \to A l^{o}$ . To prepare 5.12 kg of aluminium metal by this method would require:

Q. A certain quantity of electricity is passed through aqueous

A l_{2} (S O_{4})_{3}

and

C u S O_{4}

solutions connected in series

0.09

g of Al is deposited on cathode during electrolysis. The amount of copper deposited on cathode in grams is:

(At. wt of Al

= 27;

= 63.6

)

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On passing 0.1 Faraday of electricity through aluminium chloride, the amount of aluminium metal deposited on cathode is [MP PMT 1991]

The correct option is A 0.9 gm

On passing 0.1 Faraday of electricity through aluminium chloride, the

amount of aluminium metal deposited on cathode is

[MP PMT 1991]

The correct option is A
0.9 gm