On repeated sparking, $10$ mL of a mixture of carbon monoxide and nitrogen required $7$ mL of oxygen for combustion. What was the volume (in mL) of nitrogen? (All volumes are measured under identical conditions)

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Solution

Let the volume of $C O$ be $x$ mL and that of $N_{2}$ be $(10 - x)$ mL.
The combustion reactions are given below:
$C O_{2} + \frac{1}{2} O_{2} \to C O_{2}$
$N_{2} + O_{2} \to 2 N O$
$O_{2}$ required $= \frac{x}{2}$ mL and $N_{2}$ required $= (10 - x)$ mL
$\frac{x}{2} + (10 - x) = 7$ $⟹ x = 6$ mL
Hence, volume of $N_{2} = 10 - 6 = 4$ mL.

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On repeated sparking, 10 mL of a mixture of carbon monoxide and nitrogen required 7 mL of oxygen for combustion. What was the volume (in mL) of nitrogen? (All volumes are measured under identical conditions)

Let the volume of CO be x mL and that of N2 be (10−x) mL.The combustion reactions are given below:CO2+12O2→CO2N2+O2→2NOO2 required =x2 mL and N2 required =(10−x) mLx2+(10−x)=7 ⟹x=6 mLHence, volume of N2=10−6=4 mL.

On repeated sparking, $10$ mL of a mixture of carbon monoxide and nitrogen required $7$ mL of oxygen for combustion. What was the volume (in mL) of nitrogen? (All volumes are measured under identical conditions)