Question

In an experiment, 100 ml of ozonised oxygen was reduced to 60 ml when treated with turpentine. What would be the increase in volume if the original sample was heated until no further change occured ?(All volumes were measured under identical conditions). ?

• A. 10 ml
• B. 20 ml
• C. 30 ml
• D. 40 ml

Answer 1

The correct option is B

20 ml

Ozone in absorbed by turpentine. Hence, volume of ozone = 100 - 60 = 40 ml
Increase in volume $=\frac{3}{2}\times 40-40=20ml;$
$O_{3\left(g\right)}\to \frac{3}{2}{O}_{2\left(g\right)}$