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Question
The mass of 1 litre of ozonised oxygen at N.T.P was found to be 1.5 g. When a hundred mL of this mixture at N.T.P were treated with turpentine oil, the volume was reduced to 90 mL. The molecular mass of ozone is:
The mass of 1 litre of ozonised oxygen at N.T.P was found to be 1.5 g. When a hundred mL of this mixture at N.T.P were treated with turpentine oil, the volume was reduced to 90 mL. The molecular mass of ozone is:
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Solution
The correct option is C 48 g
As Ozone is absorbed by turpentine oil therefore volume of ozone in hundred ml of the mixture = 100−90=10 ml
therefore oxygen in the mixture= 100−10=90 ml
as 1 litre of the mixture weigh= 1.5 g, therefore average molar mass of the mixture (mass of 22.4 L at N.T.P) = 1.5×22.4=33.6 gram per mole
ratio of ozone : oxygen in the mixture = 10:90
if m is the molecular mass of ozone then
Average molecular mass of mixture:
= (10×m+90×32)100
= m+288 g=336 g
= m=48 g
As Ozone is absorbed by turpentine oil therefore volume of ozone in hundred ml of the mixture = 100−90=10 ml
therefore oxygen in the mixture= 100−10=90 ml
as 1 litre of the mixture weigh= 1.5 g, therefore average molar mass of the mixture (mass of 22.4 L at N.T.P) = 1.5×22.4=33.6 gram per mole
ratio of ozone : oxygen in the mixture = 10:90
if m is the molecular mass of ozone then
Average molecular mass of mixture:
= (10×m+90×32)100
= m+288 g=336 g
= m=48 g
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