Question

The weight of 1 litre sample of ozonised oxygen at NTP was found to be 1.5 g. When 100 ml, of the mixture at NTP were treated with turpentine oil, the volume wall reduced to 90 nil Hence, calculate the molecular weight, ozone.

Answer 1

Volume of ozone:

$=$ volume absorbed in turpentine oil
$=10mL$
Volume of $100mL$ mixture $=90mL$
Mass of $100mL$ mixture = $=\frac{10}{22400}\times M+\frac{90}{22400}\times 32$
$=0.15$
On solving, we get $M=48$
$\therefore$ Molecular mass of ozone $=48$