Question

On rotating a wheel of radius $4m$, a force of $20N$ is applied at an angle ${30}^0$ to the radius, at a point of application. The resulting torque on the wheel is:

• A. $80N-m$
• B. $60N-m$
• C. $40N-m$
• D. $20N-m$

Answer 1

Answer: (C)

$40N-m$

$|Torque|=|r\times F|=|r||F|sin\theta =4\times 20\times sin\left({30}^0\right)=80sin{30}^0=40Nm$