On simplifying this (a+b+c)2−a2−b2−c22(ab+bc+ca) we get,
A
a
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B
1b
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C
1
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D
−1
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Solution
The correct option is B1 We know the formula (a+b+c)2=a2+b2+c2+2(ab+bc+ca) =>(a+b+c)2−a2−b2−c2=2(ab+bc+ca) Hence, (a+b+c)2−a2−b2−c22(ab+bc+ca)=2(ab+bc+ca)2(ab+bc+ca)=1