On simplifying this a-b-c2-a2-b2-c2-2ab-bc-ca we get-

The correct option is B 1 We know the formula (a+b+c)^ 2 =a^ 2 +b^ 2 + c ^ 2 +2(ab+bc+ca) = gt; (a+b+c)^ 2 a^ 2 b^ 2 c ^ 2 = 2(ab+bc+ca) ...

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On simplifyin...

Question

On simplifying this $\frac{(a + b + c)^{2} - a^{2} - b^{2} - c^{2}}{2 (a b + b c + c a)}$ we get,

a

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\frac{1}{b}

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1

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Similar questions

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

a² + b² + c² - ab - bc - ca equals:

a, b, c

a^{2} = b^{2} + c^{2} - 2 b c \sqrt{1 - a^{2}}, b^{2} = c^{2} + a^{2} - 2 c a \sqrt{1 - b^{2}}, c^{2} = a^{2} + b^{2} - 2 a b \sqrt{1 - c^{2}}

a = c \sqrt{1 - b^{2}} + b \sqrt{1 - c^{2}}

a + b + c = m

a^{2} + b^{2} + c^{2} = n

2 (a b + b c + c a)

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