Question

On the annual day of school age-wise participation of students is given in the following frequency distribution table. Find the median of the students

Answer 1

Age of student	$C.I$	$c.f$	$f$
Less than $6$	$4-6$	$2$	$2$
Less than $8$	$6-8$	$6$	$4$
Less than $10$	$8-10$	$12$	$6$
Less than $12$	$10-12$	$22$	$10$
Less than $14$	$12-14$	$42$	$20$
Less than $16$	$14-16$	$67$	$25$
Less than $18$	$16-18$	$76$	$9$

$N=76$

Median$={\frac{N}{2}}^{th}$ term

$=\frac{76}{2}$

$={38}^{th}$ term

$\therefore$ Median$=38$

Median class$=12-14$