Question

On the application of a constant torque, a wheel is turned from rest through $400$ radian in $10s$. Calculate its angular acceleration. (in $rad/s^2$)

• A. $8$
  
• B. $9$
  
• C. $4$
  
• D. $5$
  

Answer 1

The correct option is A $8$

For constant torque, angular displacement equation is given by

${\theta }_t={\omega }_{0}t+\frac{1}{2}\alpha t^2$

Given that ${\omega }_0=0rad/s$, ${\theta }_t=400rad$ and $t=10sec$

$\Rightarrow 400=0\times 10+\frac{1}{2}\alpha (10{)}^2\Rightarrow \alpha =8rad/s^2$