Question

# A wheel rotating at a speed of 600 rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. The angular velocity 5 seconds after the application of the torque is nπ rad/s where n is

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Solution

## Given, Angular speed of wheel at t=0 ω0=600 rpm =600×2π60 rad/s=20π rad/s Angular speed of wheel at t=10 s ω=0 (brought to rest) From eqn. ω=ω0+αt 0=20π+α×10 α=−2π rad/s2 Angular speed of the wheel after 5 seconds will be ω=ω0+αt =20π+(−2π)×5 =10π rad/s So, n=10

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