A wheel rotating at a speed of 600rpm (revolutions per minute) about its axis is brought to rest by applying a constant torque for 10 seconds. The angular velocity 5 seconds after the application of the torque is nπrad/s where n is
A
1
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B
10
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C
5
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D
20
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Solution
The correct option is B10 Given, Angular speed of wheel at t=0 ω0=600rpm =600×2π60rad/s=20πrad/s Angular speed of wheel at t=10s ω=0 (brought to rest)
From eqn. ω=ω0+αt 0=20π+α×10 α=−2πrad/s2 Angular speed of the wheel after 5 seconds will be ω=ω0+αt =20π+(−2π)×5 =10πrad/s So, n=10