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Question

On the basis of crystal field theory explain why Co(III) forms paramagnetic octahedral complex with weak field ligands whereas it forms diamagnetic octahedral complex with strong field ligands.

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Solution

With weak field ligands: 0<P, (pairing energy) so, the electronic configuration of Co (III) will be t42ge2g i.e., it has 4 unpaired electrons and is paramagnetic.



With strong field ligands, 0>P, (pairing energy) so, pairing occurs thus, the electronic configuration will be at t62ge0g. It has no unpaired electrons and is diamagnetic.



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