On the basis of the information available from the reaction : 1 2 Al2O3, G 827KJmol 3 2 Al O 3 4 + = of O2, the minimum e.m.f. required to carry out electrolysis of Al2O3 is (F = 96500 C mol1) (1) 2.14 V (2) 4.28 V (3) 6.42 V (4) 8.56 V How to find value of n?

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On the basis of information available from the reaction:
$\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3} Δ G = - 827 K J / m o l$ of $O_{2}$ . The minimum e.m.f. required to carry out
electrolysis of $A l_{2} O_{3}$ is

Q. On the basis of the information available from the reaction:

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J m o l^{- 1}

O_{2}

, the minimum emf required to carry out the electrolysis of

A l_{2} O_{3}

[F = 96500 C m o l^{- 1}]

The minimum EMF required to carry out the electrolysis of CuO is ( Given ∆G^o for the reaction is - 827 kJ mol^-1)

On the basis of information available from the reaction

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J . m o l^{- 1}

The minimum emf required to carry out the electrolysis of $A l_{2} O_{3}$ is:

$[F = 96500 C m o l^{- 1}]$

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