Question

On the positron emission of ${}^{18}F$, the daughter nucleus formed is :

• A. ${}^{14}N$
• B. ${}^{16}O$
• C. ${}^{18}O$
• D. ${}^{19}F$
• E. ${}^{20}Ne$

Answer 1

The correct option is C ${}^{18}O$

On the positron emission of ${}^{18}F$, the daughter nucleus formed is ${}^{18}O$.
${}_9^{18}F{\to }_8^{18}O{+}_1^0\beta$
The sum of the atomic numbers on left hand side is equal to the sum of the atomic numbers on right hand side.
$9=8+1$
The sum of the mass numbers on left hand side is equal to the sum of the mass numbers on right hand side.
$18=18+0$