One angle of a quadrilateral is 100°. What is the sum of the remaining three angles of the quadrilateral?

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Solution

Let the first angle of the quadrilateral be $∠$ 1, second angle be $∠$ 2, third angle be $∠$ 3 and fourth angle be $∠$ 4
We know that the sum of the angles of a quadrilateral is 360°
∴ m $∠$ 1 + m $∠$ 2 + m $∠$ 3 + m $∠$ 4 = 360°
⇒m $∠$ 2 + m $∠$ 3 + m $∠$ 4 = 360° $-$ 100° = 260^o
Therefore, sum of the remaining three angles of the quadrilateral = 260^o

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