Question

One single of quadrilateral it of ${108}^{\circ }$ and the remaining three angles are equal. Find each of the three equal angles.

Answer 1

One angle of a quadrilaterals is of ${180}^0$ and let each of the three remaining equal angles be $x^0$

As the sum of the angles of a quadrilateral is ${360}^0$

${108}^0+x+x+x={360}^0$

$\Rightarrow 3x={360}^0-{108}^0={252}^0$

$\Rightarrow x=\frac{{252}^0}{3}={84}^0$

Hence, each of the angles be ${84}^0$