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Question

One angle of a quadrilateral is 111° and the remaining three angles are equal. Find three angles.

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Solution

Dear student,

Let ABCD be a quadrilateral whose A=111° and B=C=D ....(i)Now, A+B+C+D=360° ---(Sum of s of quadrilateral is 360°)111°+B+B+B=360° --(from (i) )3B=360°-111°3B=360°-1113B=249B=2493=83°thus, the three angles are B=C=D =83°

Regards

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