Question

One cyclic acetal form of D-galactose is shown.
Which atom is the anomeric carbon?

• A. Atom A
• B. Atom B
• C. Atom C
• D. Atom D
• E. Atom E
• F. Atom F

Answer 1

The correct option is F Atom F

Atom $F$ is anomeric in cyclic acetal form of $D$ galactose as shown in given figure of question.Anomeric carbon is stereo center anomeric carbon is either $\alpha ,\beta$ depending on position of $-OH$ group.If $-OH$ group down in cyclic form then $\alpha$ else it is $\beta$.