One cyclic acetal form of D-galactose is shown.
Which name most completely describes this cyclic acetal form?

α

-D-Galactofuranose

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β

-P-Galactofuranose

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α

-D-Galactopyranose

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β

-D-Galactopyranose

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Solution

The correct option is C $α$ -D-Galactopyranose
Full name consist of anomeric carbon, i.e whether $α, β$ ,then configuration of last chiral centre i.e D or L then name of carbohydrate with name of cyclic form.
As it is six membered ring in figure.And it is galacose cycle form its name.

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Lactose molecule is made up of β-d (-) galactopyranose and β-d (+) gluco pyraonose. The number of - OH groups present in it are

Regarding lactose, some statements are given below

A) On hydrolysis, lactose gives β-D-galactose and β-D-glucose

B) In lactose C₁ of β-D-galactose has acetal structure and C₁ of β-D-glucose has hemiacetal structure

C) In lactose molecule, β-D-galactose is a non-reducing unit and β-D-glucose is reducing unit

The correct statements are

Lactose molecule is made up of β-d (-) galactopyranose and β-d (+) gluco pyraonose. The number of - OH groups present in it are

\oplus N H_{3} - C | C O_{2}^{-} H - C H_{2} - C H_{2} - C O_{2} H

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