One end of a metal rod of length $1.0 m$ and area of cross-section $100 c m^{2}$ is maintained $100^{o} C$ . If the other end of the rod is maintained at $0^{o} C$ the quantity of heat transmitted through the rod per minute will be (coefficient of thermal conductivity of metal rod $= 100 W / k g / K$ )

3 \times 10^{3} J

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6 \times 10^{3} J

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9 \times 10^{3} J

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12 \times 10^{3} J

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Solution

The correct option is B $6 \times 10^{3} J$
$\dfrac{Q}{t} = \dfrac{KA(\theta_1-\theta_2)}{l}=\dfrac{100 \times 100 \times 10^{-4} (100 -0)}{1}$
$⟹ \frac{Q}{t} = 100 J o u l e / s e c = 6 \times 10^{3} J o u l e / m i n$

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