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Question

One end of a resistance r capacitance C and resistance 2r are connected together. The other ends are respectively connected to the positive terminals of the batteries P, Q, R having respectively e.m.f s E, E and 2E. The negative terminals of the batteries are then connected together. In this circuit, with steady current the potential drop across the capacitance is:

A
1) E/3
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B
2) E/2
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C
3) 2E/3
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D
4) E
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Solution

The correct option is A 1) E/3
In steady state ,I0=0
E=I×3r
i=E3r
[E3r×r]+E=VC+E [KVl in loop 1]
VC=E3
67755_11646_ans_5ded7ea8024b4c78aad85e47ab095f6f.png

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