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Oxides of Sulphur

One gas bleac...

Question

One gas bleaches the coloured matter by reduction temporary while the other one by oxidation permanently. The gases are respectively:

S O_{2}

and

C l_{2}

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O_{3}

and

C l_{2}

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H_{2} S

and

C O_{2}

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C l_{2}

and

C O_{2}

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Solution

The correct option is A $S O_{2}$ and $C l_{2}$
$S O_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H$ .
Hence bleaching is through reduction (temporary).

$C l_{2} + H_{2} O \to 2 H C l + [O]$
Hence bleaching is through oxidation (permanent).

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