Question

One gram of water at ${80}^{0}C$ is mixed with one gram of ice at $0^{0}C$. The resultant temperature is:

• A. ${100}^{0}C$
• B. $0^{0}C$
• C. ${80}^{0}C$
• D. ${40}^{0}C$

Answer 1

Answer: (B)

$0^{0}C$

Let us assume that the complete ice melts and final temperature is T. Then, by principle of calorimetry,

$1\left(1\right)(80-T)=1\left(80\right)+1\left(0.5\right)(T-0)$

$80-T=80+0.5T$

$T=0^{0}C$

Hence, all the ice just melts and final temperature is $0^{0}C$.