One litre of a gas at $10^{\circ} C$ is heated till both its volume and pressure are tripled. Find the new temperature.

2547 K

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2347 K

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2267 K

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2167 K

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Solution

The correct option is A
2547 K

Initial Condition -

$P_{1} = P$

$V_{1} = 1 l i t r e$

$T_{1} = 273 + 10 = 283 K$

Final Condition -

$P_{1} = 3 P$

$V_{1} = 3 l i t r e$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{P \times 1}{283} = \frac{3 P \times 3}{T_{2}}$

$T_{2} = 2547 K$

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One litre of a gas at 10∘C is heated till both its volume and pressure are tripled. Find the new temperature.

The correct option is A 2547 K Initial Condition - P1=P V1=1 litre T1=273 + 10=283 K Final Condition - P1=3P V1=3 litre P1V1T1=P2V2T2 P×1283=3P×3T2 T2=2547K

One litre of a gas at $10^{\circ} C$ is heated till both its volume and pressure are tripled. Find the new temperature.