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Question

One litre of a mixture of carbon monoxide and carbon dioxide is passed through a tube containing red hot charcoal ,the volume now becomes 1.6 litres. Volumes are measured under similar conditions. Find out the composition of gaseous mixture.

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Solution

Let volume of CO2 be X litre

Volume of CO = 1-X litre

Only CO2 will react with charcoal ( C ) to produce CO

We assume that all CO2 is converted into CO

CO + CO2 + C > 3CO

New volume will be

X CO2 converted to 2X CO

2X + 1-X =1.6

X=0.6

So in reaction mixture 0.6 Litre CO2 and 1-X or 0.4 litre CO were present.


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